13445515101041 has 4 divisors (see below), whose sum is σ = 13543657547172. Its totient is φ = 13347372654912.

The previous prime is 13445515100933. The next prime is 13445515101049. The reversal of 13445515101041 is 14010151554431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6289542346816 + 7155972754225 = 2507896^2 + 2675065^2 .

It is a cyclic number.

It is not a de Polignac number, because 13445515101041 - 2¹⁸ = 13445514838897 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13445515100992 and 13445515101010.

It is not an unprimeable number, because it can be changed into a prime (13445515101049) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49071222860 + ... + 49071223133.

It is an arithmetic number, because the mean of its divisors is an integer number (3385914386793).

Almost surely, 2^{13445515101041} is an apocalyptic number.

It is an amenable number.

13445515101041 is a deficient number, since it is larger than the sum of its proper divisors (98142446131).

13445515101041 is an equidigital number, since it uses as much as digits as its factorization.

13445515101041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 98142446130.

The product of its (nonzero) digits is 24000, while the sum is 35.

Adding to 13445515101041 its reverse (14010151554431), we get a palindrome (27455666655472).

The spelling of 13445515101041 in words is "thirteen trillion, four hundred forty-five billion, five hundred fifteen million, one hundred one thousand, forty-one".