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1344766506553 = 4916272735339
BaseRepresentation
bin10011100100011010010…
…101000111011000111001
311202120002002102121111101
4103210122111013120321
5134013040211202203
62505435513131401
7166104365463631
oct23443225073071
94676062377441
101344766506553
114793486a9148
1219875b6b9b61
1399a70825182
1449130bd76c1
1524ea90e041d
hex1391a547639

1344766506553 has 4 divisors (see below), whose sum is σ = 1344769733520. Its totient is φ = 1344763279588.

The previous prime is 1344766506539. The next prime is 1344766506571. The reversal of 1344766506553 is 3556056674431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1344766506553 - 217 = 1344766375481 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1344766506494 and 1344766506503.

It is not an unprimeable number, because it can be changed into a prime (1344766506353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 876043 + ... + 1859296.

It is an arithmetic number, because the mean of its divisors is an integer number (336192433380).

Almost surely, 21344766506553 is an apocalyptic number.

It is an amenable number.

1344766506553 is a deficient number, since it is larger than the sum of its proper divisors (3226967).

1344766506553 is an equidigital number, since it uses as much as digits as its factorization.

1344766506553 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3226966.

The product of its (nonzero) digits is 27216000, while the sum is 55.

The spelling of 1344766506553 in words is "one trillion, three hundred forty-four billion, seven hundred sixty-six million, five hundred six thousand, five hundred fifty-three".

Divisors: 1 491627 2735339 1344766506553