Base | Representation |
---|---|
bin | 11110100101010000010100… |
… | …000000001101100111000011 |
3 | 122122020012221222120222212212 |
4 | 132211100110000031213003 |
5 | 120112133114022112403 |
6 | 1154021052303212335 |
7 | 40221262222503464 |
oct | 3645202400154703 |
9 | 578205858528785 |
10 | 134501531441603 |
11 | 39946863062007 |
12 | 1310336a8a70ab |
13 | 5a0859487bb41 |
14 | 252dca1c8ad6b |
15 | 1083a608424d8 |
hex | 7a541400d9c3 |
134501531441603 has 4 divisors (see below), whose sum is σ = 134649824200440. Its totient is φ = 134353238682768.
The previous prime is 134501531441573. The next prime is 134501531441623. The reversal of 134501531441603 is 306144135105431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134501531441603 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (134501531441623) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 74146378058 + ... + 74146379871.
It is an arithmetic number, because the mean of its divisors is an integer number (33662456050110).
Almost surely, 2134501531441603 is an apocalyptic number.
134501531441603 is a deficient number, since it is larger than the sum of its proper divisors (148292758837).
134501531441603 is an equidigital number, since it uses as much as digits as its factorization.
134501531441603 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 148292758836.
The product of its (nonzero) digits is 259200, while the sum is 41.
The spelling of 134501531441603 in words is "one hundred thirty-four trillion, five hundred one billion, five hundred thirty-one million, four hundred forty-one thousand, six hundred three".
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