13450496803 has 4 divisors (see below), whose sum is σ = 13452915888. Its totient is φ = 13448077720.

The previous prime is 13450496791. The next prime is 13450496819. The reversal of 13450496803 is 30869405431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30869405431 = 19 ⋅1624705549.

It is a cyclic number.

It is not a de Polignac number, because 13450496803 - 2³³ = 4860562211 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13450496803.

It is not an unprimeable number, because it can be changed into a prime (13450496893) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1201183 + ... + 1212328.

It is an arithmetic number, because the mean of its divisors is an integer number (3363228972).

Almost surely, 2^13450496803 is an apocalyptic number.

13450496803 is a deficient number, since it is larger than the sum of its proper divisors (2419085).

13450496803 is an equidigital number, since it uses as much as digits as its factorization.

13450496803 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2419084.

The product of its (nonzero) digits is 311040, while the sum is 43.

The spelling of 13450496803 in words is "thirteen billion, four hundred fifty million, four hundred ninety-six thousand, eight hundred three".