Base | Representation |
---|---|
bin | 1100001110111110110000… |
… | …0010000000100011110011 |
3 | 1202121221200100012200120112 |
4 | 3003233230002000203303 |
5 | 3230342134123201311 |
6 | 44335311315131535 |
7 | 2555560526106203 |
oct | 303575402004363 |
9 | 52557610180515 |
10 | 13451502553331 |
11 | 4316828569757 |
12 | 1612ba8ba3bab |
13 | 76761844098b |
14 | 3470b02c4403 |
15 | 184d877c628b |
hex | c3bec0808f3 |
13451502553331 has 4 divisors (see below), whose sum is σ = 13815056676432. Its totient is φ = 13087948430232.
The previous prime is 13451502553319. The next prime is 13451502553373. The reversal of 13451502553331 is 13335520515431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13451502553331 - 218 = 13451502291187 is a prime.
It is a super-2 number, since 2×134515025533312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13451502853331) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 181777061495 + ... + 181777061568.
It is an arithmetic number, because the mean of its divisors is an integer number (3453764169108).
Almost surely, 213451502553331 is an apocalyptic number.
13451502553331 is a deficient number, since it is larger than the sum of its proper divisors (363554123101).
13451502553331 is an equidigital number, since it uses as much as digits as its factorization.
13451502553331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 363554123100.
The product of its (nonzero) digits is 405000, while the sum is 41.
The spelling of 13451502553331 in words is "thirteen trillion, four hundred fifty-one billion, five hundred two million, five hundred fifty-three thousand, three hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •