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13453034451 = 35647794111
BaseRepresentation
bin11001000011101110…
…10000001111010011
31021201120020221220020
430201313100033103
5210022434100301
610102533114523
7654243622533
oct144167201723
937646227806
1013453034451
11578398399a
122735488a43
1313651c191c
149189b74c3
1553b0de436
hex321dd03d3

13453034451 has 8 divisors (see below), whose sum is σ = 17940578304. Its totient is φ = 8967090120.

The previous prime is 13453034429. The next prime is 13453034459. The reversal of 13453034451 is 15443035431.

13453034451 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13453034451 - 217 = 13452903379 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13453034459) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 380115 + ... + 413996.

It is an arithmetic number, because the mean of its divisors is an integer number (2242572288).

Almost surely, 213453034451 is an apocalyptic number.

13453034451 is a deficient number, since it is larger than the sum of its proper divisors (4487543853).

13453034451 is an equidigital number, since it uses as much as digits as its factorization.

13453034451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 799761.

The product of its (nonzero) digits is 43200, while the sum is 33.

Adding to 13453034451 its reverse (15443035431), we get a palindrome (28896069882).

The spelling of 13453034451 in words is "thirteen billion, four hundred fifty-three million, thirty-four thousand, four hundred fifty-one".

Divisors: 1 3 5647 16941 794111 2382333 4484344817 13453034451