Base | Representation |
---|---|
bin | 10011100100111011111… |
… | …011010001000000011001 |
3 | 11202121112101000221112222 |
4 | 103210323323101000121 |
5 | 134020214004434140 |
6 | 2510011450113425 |
7 | 166124351433305 |
oct | 23447373210031 |
9 | 4677471027488 |
10 | 1345330155545 |
11 | 479607888a62 |
12 | 19889841b875 |
13 | 99b3053409c |
14 | 491859dad05 |
15 | 24edd82c5b5 |
hex | 1393bed1019 |
1345330155545 has 4 divisors (see below), whose sum is σ = 1614396186660. Its totient is φ = 1076264124432.
The previous prime is 1345330155527. The next prime is 1345330155583. The reversal of 1345330155545 is 5455510335431.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 491855352976 + 853474802569 = 701324^2 + 923837^2 .
It is a cyclic number.
It is not a de Polignac number, because 1345330155545 - 212 = 1345330151449 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1345330155496 and 1345330155505.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 134533015550 + ... + 134533015559.
It is an arithmetic number, because the mean of its divisors is an integer number (403599046665).
Almost surely, 21345330155545 is an apocalyptic number.
It is an amenable number.
1345330155545 is a deficient number, since it is larger than the sum of its proper divisors (269066031115).
1345330155545 is an equidigital number, since it uses as much as digits as its factorization.
1345330155545 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 269066031114.
The product of its (nonzero) digits is 1350000, while the sum is 44.
The spelling of 1345330155545 in words is "one trillion, three hundred forty-five billion, three hundred thirty million, one hundred fifty-five thousand, five hundred forty-five".
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