Search a number
-
+
13454364203 = 71922052029
BaseRepresentation
bin11001000011111000…
…10100111000101011
31021201122202111222022
430201330110320223
5210023304123303
610103021415055
7654261131420
oct144174247053
937648674868
1013454364203
115784701a65
122735a0a48b
131365568c67
14918c41d47
1553b2a3438
hex321f14e2b

13454364203 has 4 divisors (see below), whose sum is σ = 15376416240. Its totient is φ = 11532312168.

The previous prime is 13454364191. The next prime is 13454364221. The reversal of 13454364203 is 30246345431.

13454364203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13454364203 - 218 = 13454102059 is a prime.

It is a super-2 number, since 2×134543642032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13454364223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 961026008 + ... + 961026021.

It is an arithmetic number, because the mean of its divisors is an integer number (3844104060).

Almost surely, 213454364203 is an apocalyptic number.

13454364203 is a deficient number, since it is larger than the sum of its proper divisors (1922052037).

13454364203 is an equidigital number, since it uses as much as digits as its factorization.

13454364203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1922052036.

The product of its (nonzero) digits is 103680, while the sum is 35.

The spelling of 13454364203 in words is "thirteen billion, four hundred fifty-four million, three hundred sixty-four thousand, two hundred three".

Divisors: 1 7 1922052029 13454364203