Base | Representation |
---|---|
bin | 10011100101000111010… |
… | …101001100100110001011 |
3 | 11202122000201002101101001 |
4 | 103211013111030212023 |
5 | 134021112001040403 |
6 | 2510042443235431 |
7 | 166132164031405 |
oct | 23450725144613 |
9 | 4678021071331 |
10 | 1345521502603 |
11 | 4796a58a0923 |
12 | 198930518b77 |
13 | 99b6107b9b5 |
14 | 491a31a9b75 |
15 | 25000527c1d |
hex | 1394754c98b |
1345521502603 has 4 divisors (see below), whose sum is σ = 1361732605128. Its totient is φ = 1329310400080.
The previous prime is 1345521502583. The next prime is 1345521502643. The reversal of 1345521502603 is 3062051255431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1345521502603 is a prime.
It is a super-2 number, since 2×13455215026032 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1345521502643) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8105551138 + ... + 8105551303.
It is an arithmetic number, because the mean of its divisors is an integer number (340433151282).
Almost surely, 21345521502603 is an apocalyptic number.
1345521502603 is a deficient number, since it is larger than the sum of its proper divisors (16211102525).
1345521502603 is an equidigital number, since it uses as much as digits as its factorization.
1345521502603 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16211102524.
The product of its (nonzero) digits is 108000, while the sum is 37.
The spelling of 1345521502603 in words is "one trillion, three hundred forty-five billion, five hundred twenty-one million, five hundred two thousand, six hundred three".
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