Base | Representation |
---|---|
bin | 111110101100000111… |
… | …0000010101110000011 |
3 | 110212111011220221122221 |
4 | 1331120032002232003 |
5 | 4201202224443324 |
6 | 141502340511511 |
7 | 12504052435444 |
oct | 1753016025603 |
9 | 425434827587 |
10 | 134624062339 |
11 | 52103856658 |
12 | 221113ab597 |
13 | c905b982b0 |
14 | 673166b2cb |
15 | 377dcab0e4 |
hex | 1f58382b83 |
134624062339 has 8 divisors (see below), whose sum is σ = 144989267360. Its totient is φ = 124260215616.
The previous prime is 134624062337. The next prime is 134624062361. The reversal of 134624062339 is 933260426431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 134624062339 - 21 = 134624062337 is a prime.
It is a super-3 number, since 3×1346240623393 (a number of 34 digits) contains 333 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 134624062295 and 134624062304.
It is not an unprimeable number, because it can be changed into a prime (134624062337) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 128874 + ... + 534655.
It is an arithmetic number, because the mean of its divisors is an integer number (18123658420).
Almost surely, 2134624062339 is an apocalyptic number.
134624062339 is a deficient number, since it is larger than the sum of its proper divisors (10365205021).
134624062339 is a wasteful number, since it uses less digits than its factorization.
134624062339 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 679149.
The product of its (nonzero) digits is 559872, while the sum is 43.
The spelling of 134624062339 in words is "one hundred thirty-four billion, six hundred twenty-four million, sixty-two thousand, three hundred thirty-nine".
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