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13464403430041 = 21163812338531
BaseRepresentation
bin1100001111101110110011…
…1110111100101010011001
31202200011222102111010110001
43003323230332330222121
53231100044234230131
644345243405453001
72556525316542514
oct303735476745231
952604872433401
1013464403430041
1143212487a1333
1216155a9571161
137688c3117c35
14347975809d7b
15185390198261
hexc3eecfbca99

13464403430041 has 4 divisors (see below), whose sum is σ = 13528215768784. Its totient is φ = 13400591091300.

The previous prime is 13464403430039. The next prime is 13464403430083. The reversal of 13464403430041 is 14003430446431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13464403430041 - 21 = 13464403430039 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13464403430011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31906169055 + ... + 31906169476.

It is an arithmetic number, because the mean of its divisors is an integer number (3382053942196).

Almost surely, 213464403430041 is an apocalyptic number.

It is an amenable number.

13464403430041 is a deficient number, since it is larger than the sum of its proper divisors (63812338743).

13464403430041 is an equidigital number, since it uses as much as digits as its factorization.

13464403430041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 63812338742.

The product of its (nonzero) digits is 165888, while the sum is 37.

Adding to 13464403430041 its reverse (14003430446431), we get a palindrome (27467833876472).

The spelling of 13464403430041 in words is "thirteen trillion, four hundred sixty-four billion, four hundred three million, four hundred thirty thousand, forty-one".

Divisors: 1 211 63812338531 13464403430041