13481113 has 4 divisors (see below), whose sum is σ = 13651840. Its totient is φ = 13310388.

The previous prime is 13481107. The next prime is 13481131. The reversal of 13481113 is 31118431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31118431 = 2221 ⋅14011.

It is a cyclic number.

It is not a de Polignac number, because 13481113 - 2⁵ = 13481081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13481173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85245 + ... + 85402.

It is an arithmetic number, because the mean of its divisors is an integer number (3412960).

Almost surely, 2^13481113 is an apocalyptic number.

It is an amenable number.

13481113 is a deficient number, since it is larger than the sum of its proper divisors (170727).

13481113 is an equidigital number, since it uses as much as digits as its factorization.

13481113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 170726.

The product of its digits is 288, while the sum is 22.

The square root of 13481113 is about 3671.6635194418. The cubic root of 13481113 is about 237.9990643279. Note that the first 3 decimals are identical.

Adding to 13481113 its reverse (31118431), we get a palindrome (44599544).

The spelling of 13481113 in words is "thirteen million, four hundred eighty-one thousand, one hundred thirteen".