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1348182644649 = 3449394214883
BaseRepresentation
bin10011100111100101111…
…100101001011110101001
311202212220011111101222120
4103213211330221132221
5134042034224112044
62511202504541453
7166255136254131
oct23474574513651
94685804441876
101348182644649
1147a840a57275
12199353781889
139a1964ab669
14493767a5ac1
1525108e84519
hex139e5f297a9

1348182644649 has 4 divisors (see below), whose sum is σ = 1797576859536. Its totient is φ = 898788429764.

The previous prime is 1348182644623. The next prime is 1348182644651. The reversal of 1348182644649 is 9464462818431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1348182644649 - 213 = 1348182636457 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1348182644592 and 1348182644601.

It is not an unprimeable number, because it can be changed into a prime (1348182644609) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 224697107439 + ... + 224697107444.

It is an arithmetic number, because the mean of its divisors is an integer number (449394214884).

Almost surely, 21348182644649 is an apocalyptic number.

It is an amenable number.

1348182644649 is a deficient number, since it is larger than the sum of its proper divisors (449394214887).

1348182644649 is an equidigital number, since it uses as much as digits as its factorization.

1348182644649 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 449394214886.

The product of its digits is 31850496, while the sum is 60.

The spelling of 1348182644649 in words is "one trillion, three hundred forty-eight billion, one hundred eighty-two million, six hundred forty-four thousand, six hundred forty-nine".

Divisors: 1 3 449394214883 1348182644649