Base | Representation |
---|---|
bin | 10000000101010… |
… | …00000001011001 |
3 | 100101211221011111 |
4 | 20002220001121 |
5 | 234013442240 |
6 | 21215300321 |
7 | 3225452536 |
oct | 1002500131 |
9 | 311757144 |
10 | 134905945 |
11 | 6a172919 |
12 | 3921a6a1 |
13 | 21c45805 |
14 | 13cb9d8d |
15 | bc9c1ea |
hex | 80a8059 |
134905945 has 4 divisors (see below), whose sum is σ = 161887140. Its totient is φ = 107924752.
The previous prime is 134905889. The next prime is 134905963. The reversal of 134905945 is 549509431.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 30702681 + 104203264 = 5541^2 + 10208^2 .
It is a cyclic number.
It is not a de Polignac number, because 134905945 - 213 = 134897753 is a prime.
It is a super-2 number, since 2×1349059452 = 36399227992686050, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 134905898 and 134905907.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13490590 + ... + 13490599.
It is an arithmetic number, because the mean of its divisors is an integer number (40471785).
Almost surely, 2134905945 is an apocalyptic number.
It is an amenable number.
134905945 is a deficient number, since it is larger than the sum of its proper divisors (26981195).
134905945 is an equidigital number, since it uses as much as digits as its factorization.
134905945 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26981194.
The product of its (nonzero) digits is 97200, while the sum is 40.
The square root of 134905945 is about 11614.9018506400. The cubic root of 134905945 is about 512.8736216676.
The spelling of 134905945 in words is "one hundred thirty-four million, nine hundred five thousand, nine hundred forty-five".
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