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134962591979 = 162641829819
BaseRepresentation
bin111110110110001100…
…1011011100011101011
3110220100202221001000202
41331230121123203223
54202400410420404
6142000112422415
712515333050355
oct1755431334353
9426322831022
10134962591979
1152267956a16
12221a6847a0b
13c95b0665a7
1467645d00d5
15379d87b21e
hex1f6c65b8eb

134962591979 has 4 divisors (see below), whose sum is σ = 134963584440. Its totient is φ = 134961599520.

The previous prime is 134962591937. The next prime is 134962591997. The reversal of 134962591979 is 979195269431.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 134962591979 - 212 = 134962587883 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134962591999) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 252269 + ... + 577550.

It is an arithmetic number, because the mean of its divisors is an integer number (33740896110).

Almost surely, 2134962591979 is an apocalyptic number.

134962591979 is a deficient number, since it is larger than the sum of its proper divisors (992461).

134962591979 is an equidigital number, since it uses as much as digits as its factorization.

134962591979 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 992460.

The product of its digits is 33067440, while the sum is 65.

The spelling of 134962591979 in words is "one hundred thirty-four billion, nine hundred sixty-two million, five hundred ninety-one thousand, nine hundred seventy-nine".

Divisors: 1 162641 829819 134962591979