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1349934644131 = 1779407920243
BaseRepresentation
bin10011101001001110010…
…111111111101110100011
311210001102021012012110021
4103221032113333232203
5134104131232103011
62512052412214311
7166346432102263
oct23511627775643
94701367165407
101349934644131
1148055aa06427
1219976246a397
139a3b5463448
14494a13457a3
15251acbaa471
hex13a4e5ffba3

1349934644131 has 4 divisors (see below), whose sum is σ = 1429342564392. Its totient is φ = 1270526723872.

The previous prime is 1349934644129. The next prime is 1349934644137. The reversal of 1349934644131 is 1314464399431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1349934644131 - 21 = 1349934644129 is a prime.

It is a super-2 number, since 2×13499346441312 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1349934644137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39703960105 + ... + 39703960138.

It is an arithmetic number, because the mean of its divisors is an integer number (357335641098).

Almost surely, 21349934644131 is an apocalyptic number.

1349934644131 is a deficient number, since it is larger than the sum of its proper divisors (79407920261).

1349934644131 is an equidigital number, since it uses as much as digits as its factorization.

1349934644131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 79407920260.

The product of its digits is 3359232, while the sum is 52.

The spelling of 1349934644131 in words is "one trillion, three hundred forty-nine billion, nine hundred thirty-four million, six hundred forty-four thousand, one hundred thirty-one".

Divisors: 1 17 79407920243 1349934644131