13500041 has 4 divisors (see below), whose sum is σ = 13509012. Its totient is φ = 13491072.

The previous prime is 13500037. The next prime is 13500049. The reversal of 13500041 is 14000531.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 14000531 = 181 ⋅77351.

It can be written as a sum of positive squares in 2 ways, for example, as 12988816 + 511225 = 3604^2 + 715^2 .

It is a cyclic number.

It is not a de Polignac number, because 13500041 - 2² = 13500037 is a prime.

It is a super-2 number, since 2×13500041² = 364502214003362, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13499989 and 13500025.

It is not an unprimeable number, because it can be changed into a prime (13500049) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1616 + ... + 5441.

It is an arithmetic number, because the mean of its divisors is an integer number (3377253).

Almost surely, 2^13500041 is an apocalyptic number.

It is an amenable number.

13500041 is a deficient number, since it is larger than the sum of its proper divisors (8971).

13500041 is an equidigital number, since it uses as much as digits as its factorization.

13500041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8970.

The product of its (nonzero) digits is 60, while the sum is 14.

The square root of 13500041 is about 3674.2401935638. The cubic root of 13500041 is about 238.1103988448.

Adding to 13500041 its reverse (14000531), we get a palindrome (27500572).

The spelling of 13500041 in words is "thirteen million, five hundred thousand, forty-one".