135000423131 has 4 divisors (see below), whose sum is σ = 154286197872. Its totient is φ = 115714648392.

The previous prime is 135000423109. The next prime is 135000423157. The reversal of 135000423131 is 131324000531.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 131324000531 = 683 ⋅192275257.

It is not a de Polignac number, because 135000423131 - 2¹⁰ = 135000422107 is a prime.

It is a super-2 number, since 2×135000423131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 135000423097 and 135000423106.

It is not an unprimeable number, because it can be changed into a prime (135000423161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9642887360 + ... + 9642887373.

It is an arithmetic number, because the mean of its divisors is an integer number (38571549468).

Almost surely, 2^135000423131 is an apocalyptic number.

135000423131 is a deficient number, since it is larger than the sum of its proper divisors (19285774741).

135000423131 is an equidigital number, since it uses as much as digits as its factorization.

135000423131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19285774740.

The product of its (nonzero) digits is 1080, while the sum is 23.

Adding to 135000423131 its reverse (131324000531), we get a palindrome (266324423662).

The spelling of 135000423131 in words is "one hundred thirty-five billion, four hundred twenty-three thousand, one hundred thirty-one".