Base | Representation |
---|---|
bin | 11001001001010101… |
… | …10111110000110011 |
3 | 1021211211212011021201 |
4 | 30210222313300303 |
5 | 210122012320430 |
6 | 10111334232031 |
7 | 655355061526 |
oct | 144452676063 |
9 | 37754764251 |
10 | 13500120115 |
11 | 57a8514069 |
12 | 27491b5617 |
13 | 1371b99671 |
14 | 920d52bbd |
15 | 5402e08ca |
hex | 324ab7c33 |
13500120115 has 8 divisors (see below), whose sum is σ = 16232354208. Its totient is φ = 10778622720.
The previous prime is 13500120077. The next prime is 13500120167. The reversal of 13500120115 is 51102100531.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13500120115 - 211 = 13500118067 is a prime.
It is a super-2 number, since 2×135001201152 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13500120092 and 13500120101.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2681406 + ... + 2686435.
It is an arithmetic number, because the mean of its divisors is an integer number (2029044276).
Almost surely, 213500120115 is an apocalyptic number.
13500120115 is a deficient number, since it is larger than the sum of its proper divisors (2732234093).
13500120115 is an equidigital number, since it uses as much as digits as its factorization.
13500120115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5368349.
The product of its (nonzero) digits is 150, while the sum is 19.
Adding to 13500120115 its reverse (51102100531), we get a palindrome (64602220646).
The spelling of 13500120115 in words is "thirteen billion, five hundred million, one hundred twenty thousand, one hundred fifteen".
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