13500130003 has 4 divisors (see below), whose sum is σ = 13500647728. Its totient is φ = 13499612280.

The previous prime is 13500129991. The next prime is 13500130009. The reversal of 13500130003 is 30003100531.

13500130003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30003100531 = 33053 ⋅907727.

It is a cyclic number.

It is not a de Polignac number, because 13500130003 - 2²¹ = 13498032851 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13500130009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 217551 + ... + 272632.

It is an arithmetic number, because the mean of its divisors is an integer number (3375161932).

Almost surely, 2^13500130003 is an apocalyptic number.

13500130003 is a deficient number, since it is larger than the sum of its proper divisors (517725).

13500130003 is an equidigital number, since it uses as much as digits as its factorization.

13500130003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 517724.

The product of its (nonzero) digits is 135, while the sum is 16.

Adding to 13500130003 its reverse (30003100531), we get a palindrome (43503230534).

The spelling of 13500130003 in words is "thirteen billion, five hundred million, one hundred thirty thousand, three".