Base | Representation |
---|---|
bin | 1100010001110100100010… |
… | …0111100100110101111011 |
3 | 1202210121122011020112022020 |
4 | 3010131020213210311323 |
5 | 3232142103414423103 |
6 | 44413541421325523 |
7 | 2562236014151520 |
oct | 304351047446573 |
9 | 52717564215266 |
10 | 13500300545403 |
11 | 4335499784421 |
12 | 16205474068a3 |
13 | 76c0c41652b9 |
14 | 3495bd121147 |
15 | 186291885753 |
hex | c47489e4d7b |
13500300545403 has 16 divisors (see below), whose sum is σ = 20590303668480. Its totient is φ = 7707551033376.
The previous prime is 13500300545399. The next prime is 13500300545429. The reversal of 13500300545403 is 30454500300531.
It is not a de Polignac number, because 13500300545403 - 22 = 13500300545399 is a prime.
It is a super-2 number, since 2×135003005454032 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13500300545003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 287743533 + ... + 287790446.
It is an arithmetic number, because the mean of its divisors is an integer number (1286893979280).
Almost surely, 213500300545403 is an apocalyptic number.
13500300545403 is a deficient number, since it is larger than the sum of its proper divisors (7090003123077).
13500300545403 is a wasteful number, since it uses less digits than its factorization.
13500300545403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 575535106.
The product of its (nonzero) digits is 54000, while the sum is 33.
Adding to 13500300545403 its reverse (30454500300531), we get a palindrome (43954800845934).
The spelling of 13500300545403 in words is "thirteen trillion, five hundred billion, three hundred million, five hundred forty-five thousand, four hundred three".
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