13500311131 has 4 divisors (see below), whose sum is σ = 13500903064. Its totient is φ = 13499719200.

The previous prime is 13500311113. The next prime is 13500311141. The reversal of 13500311131 is 13111300531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13500311131 - 2²³ = 13491922523 is a prime.

It is a super-2 number, since 2×13500311131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13500311099 and 13500311108.

It is not an unprimeable number, because it can be changed into a prime (13500311141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 260325 + ... + 307846.

It is an arithmetic number, because the mean of its divisors is an integer number (3375225766).

Almost surely, 2^13500311131 is an apocalyptic number.

13500311131 is a deficient number, since it is larger than the sum of its proper divisors (591933).

13500311131 is an equidigital number, since it uses as much as digits as its factorization.

13500311131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 591932.

The product of its (nonzero) digits is 135, while the sum is 19.

Adding to 13500311131 its reverse (13111300531), we get a palindrome (26611611662).

The spelling of 13500311131 in words is "thirteen billion, five hundred million, three hundred eleven thousand, one hundred thirty-one".