Base | Representation |
---|---|
bin | 10011101001010100101… |
… | …011001011000001100001 |
3 | 11210001200122001211021220 |
4 | 103221110223023001201 |
5 | 134104340311200213 |
6 | 2512111105405253 |
7 | 166352154334260 |
oct | 23512453130141 |
9 | 4701618054256 |
10 | 1350040334433 |
11 | 48060463408a |
12 | 199791939829 |
13 | 9a401319c9b |
14 | 494b13b85d7 |
15 | 251b70d5e23 |
hex | 13a54acb061 |
1350040334433 has 16 divisors (see below), whose sum is σ = 2057273473920. Its totient is φ = 771425686656.
The previous prime is 1350040334431. The next prime is 1350040334443. The reversal of 1350040334433 is 3344330400531.
It is not a de Polignac number, because 1350040334433 - 21 = 1350040334431 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1350040334394 and 1350040334403.
It is not an unprimeable number, because it can be changed into a prime (1350040334431) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 431910 + ... + 1699007.
It is an arithmetic number, because the mean of its divisors is an integer number (128579592120).
Almost surely, 21350040334433 is an apocalyptic number.
It is an amenable number.
1350040334433 is a deficient number, since it is larger than the sum of its proper divisors (707233139487).
1350040334433 is a wasteful number, since it uses less digits than its factorization.
1350040334433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2161096.
The product of its (nonzero) digits is 77760, while the sum is 33.
Adding to 1350040334433 its reverse (3344330400531), we get a palindrome (4694370734964).
The spelling of 1350040334433 in words is "one trillion, three hundred fifty billion, forty million, three hundred thirty-four thousand, four hundred thirty-three".
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