13500433536403 has 16 divisors (see below), whose sum is σ = 15202987656192. Its totient is φ = 11877094404000.

The previous prime is 13500433536397. The next prime is 13500433536433. The reversal of 13500433536403 is 30463533400531.

It is a cyclic number.

It is not a de Polignac number, because 13500433536403 - 2⁵ = 13500433536371 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13500433536433) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 62001400 + ... + 62218762.

It is an arithmetic number, because the mean of its divisors is an integer number (950186728512).

Almost surely, 2^{13500433536403} is an apocalyptic number.

13500433536403 is a deficient number, since it is larger than the sum of its proper divisors (1702554119789).

13500433536403 is a wasteful number, since it uses less digits than its factorization.

13500433536403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 399546.

The product of its (nonzero) digits is 583200, while the sum is 40.

Adding to 13500433536403 its reverse (30463533400531), we get a palindrome (43963966936934).

The spelling of 13500433536403 in words is "thirteen trillion, five hundred billion, four hundred thirty-three million, five hundred thirty-six thousand, four hundred three".