1350050301113 has 4 divisors (see below), whose sum is σ = 1351976193828. Its totient is φ = 1348124408400.

The previous prime is 1350050301107. The next prime is 1350050301161. The reversal of 1350050301113 is 3111030500531.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 492624304384 + 857425996729 = 701872^2 + 925973^2 .

It is a cyclic number.

It is not a de Polignac number, because 1350050301113 - 2⁸ = 1350050300857 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1350050601113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 962945306 + ... + 962946707.

It is an arithmetic number, because the mean of its divisors is an integer number (337994048457).

Almost surely, 2^{1350050301113} is an apocalyptic number.

It is an amenable number.

1350050301113 is a deficient number, since it is larger than the sum of its proper divisors (1925892715).

1350050301113 is an equidigital number, since it uses as much as digits as its factorization.

1350050301113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1925892714.

The product of its (nonzero) digits is 675, while the sum is 23.

Adding to 1350050301113 its reverse (3111030500531), we get a palindrome (4461080801644).

The spelling of 1350050301113 in words is "one trillion, three hundred fifty billion, fifty million, three hundred one thousand, one hundred thirteen".