13501001401 has 4 divisors (see below), whose sum is σ = 14295177972. Its totient is φ = 12706824832.

The previous prime is 13501001387. The next prime is 13501001413. The reversal of 13501001401 is 10410010531.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 10410010531 = 113 ⋅92123987.

It can be written as a sum of positive squares in 2 ways, for example, as 11475551376 + 2025450025 = 107124^2 + 45005^2 .

It is a cyclic number.

It is not a de Polignac number, because 13501001401 - 2⁹ = 13501000889 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13501001441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 397088260 + ... + 397088293.

It is an arithmetic number, because the mean of its divisors is an integer number (3573794493).

Almost surely, 2^13501001401 is an apocalyptic number.

It is an amenable number.

13501001401 is a deficient number, since it is larger than the sum of its proper divisors (794176571).

13501001401 is an equidigital number, since it uses as much as digits as its factorization.

13501001401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 794176570.

The product of its (nonzero) digits is 60, while the sum is 16.

Adding to 13501001401 its reverse (10410010531), we get a palindrome (23911011932).

The spelling of 13501001401 in words is "thirteen billion, five hundred one million, one thousand, four hundred one".