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1350113 = 6122133
BaseRepresentation
bin101001001100111100001
32112121000012
411021213201
5321200423
644534305
714322122
oct5114741
92477005
101350113
118423a6
12551395
133836ab
14272049
151ba078
hex1499e1

1350113 has 4 divisors (see below), whose sum is σ = 1372308. Its totient is φ = 1327920.

The previous prime is 1350101. The next prime is 1350119. The reversal of 1350113 is 3110531.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 283024 + 1067089 = 532^2 + 1033^2 .

It is a cyclic number.

It is not a de Polignac number, because 1350113 - 26 = 1350049 is a prime.

It is a super-5 number, since 5×13501135 (a number of 32 digits) contains 55555 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1350119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11006 + ... + 11127.

It is an arithmetic number, because the mean of its divisors is an integer number (343077).

21350113 is an apocalyptic number.

It is an amenable number.

1350113 is a deficient number, since it is larger than the sum of its proper divisors (22195).

1350113 is an equidigital number, since it uses as much as digits as its factorization.

1350113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22194.

The product of its (nonzero) digits is 45, while the sum is 14.

The square root of 1350113 is about 1161.9436303023. The cubic root of 1350113 is about 110.5240285440.

Adding to 1350113 its reverse (3110531), we get a palindrome (4460644).

The spelling of 1350113 in words is "one million, three hundred fifty thousand, one hundred thirteen".

Divisors: 1 61 22133 1350113