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135011323 = 617218819
BaseRepresentation
bin10000000110000…
…01101111111011
3100102001021201101
420003001233323
5234030330243
621221432231
73226402006
oct1003015773
9312037641
10135011323
116a235007
123926b677
1321c81775
1413d0653d
15bcbd54d
hex80c1bfb

135011323 has 4 divisors (see below), whose sum is σ = 135230760. Its totient is φ = 134791888.

The previous prime is 135011291. The next prime is 135011347. The reversal of 135011323 is 323110531.

135011323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 135011323 - 25 = 135011291 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 135011323.

It is not an unprimeable number, because it can be changed into a prime (135011923) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 108793 + ... + 110026.

It is an arithmetic number, because the mean of its divisors is an integer number (33807690).

Almost surely, 2135011323 is an apocalyptic number.

135011323 is a deficient number, since it is larger than the sum of its proper divisors (219437).

135011323 is an equidigital number, since it uses as much as digits as its factorization.

135011323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 219436.

The product of its (nonzero) digits is 270, while the sum is 19.

The square root of 135011323 is about 11619.4372927436. The cubic root of 135011323 is about 513.0071258670.

Adding to 135011323 its reverse (323110531), we get a palindrome (458121854).

The spelling of 135011323 in words is "one hundred thirty-five million, eleven thousand, three hundred twenty-three".

Divisors: 1 617 218819 135011323