13501253334201 has 4 divisors (see below), whose sum is σ = 18001671112272. Its totient is φ = 9000835556132.

The previous prime is 13501253334067. The next prime is 13501253334211. The reversal of 13501253334201 is 10243335210531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13501253334201 - 2¹⁷ = 13501253203129 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13501253334211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2250208889031 + ... + 2250208889036.

It is an arithmetic number, because the mean of its divisors is an integer number (4500417778068).

Almost surely, 2^{13501253334201} is an apocalyptic number.

It is an amenable number.

13501253334201 is a deficient number, since it is larger than the sum of its proper divisors (4500417778071).

13501253334201 is an equidigital number, since it uses as much as digits as its factorization.

13501253334201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4500417778070.

The product of its (nonzero) digits is 32400, while the sum is 33.

Adding to 13501253334201 its reverse (10243335210531), we get a palindrome (23744588544732).

The spelling of 13501253334201 in words is "thirteen trillion, five hundred one billion, two hundred fifty-three million, three hundred thirty-four thousand, two hundred one".