1350300113 has 4 divisors (see below), whose sum is σ = 1421368560. Its totient is φ = 1279231668.

The previous prime is 1350300097. The next prime is 1350300121. The reversal of 1350300113 is 3110030531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3110030531 = 241 ⋅12904691.

It is a cyclic number.

It is not a de Polignac number, because 1350300113 - 2⁴ = 1350300097 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1350300091 and 1350300100.

It is not an unprimeable number, because it can be changed into a prime (1350300143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35534195 + ... + 35534232.

It is an arithmetic number, because the mean of its divisors is an integer number (355342140).

Almost surely, 2^1350300113 is an apocalyptic number.

It is an amenable number.

1350300113 is a deficient number, since it is larger than the sum of its proper divisors (71068447).

1350300113 is an equidigital number, since it uses as much as digits as its factorization.

1350300113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 71068446.

The product of its (nonzero) digits is 135, while the sum is 17.

The square root of 1350300113 is about 36746.4299354373. The cubic root of 1350300113 is about 1105.2913417274.

Adding to 1350300113 its reverse (3110030531), we get a palindrome (4460330644).

The spelling of 1350300113 in words is "one billion, three hundred fifty million, three hundred thousand, one hundred thirteen".