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135031115 = 527006223
BaseRepresentation
bin10000000110001…
…10100101001011
3100102002021212102
420003012211023
5234031443430
621222104015
73226513502
oct1003064513
9312067772
10135031115
116a24896a
123927b00b
1321c8a78b
1413d0d839
15bcc4345
hex80c694b

135031115 has 4 divisors (see below), whose sum is σ = 162037344. Its totient is φ = 108024888.

The previous prime is 135031109. The next prime is 135031139. The reversal of 135031115 is 511130531.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 511130531 = 3311544201.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-135031115 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13503107 + ... + 13503116.

It is an arithmetic number, because the mean of its divisors is an integer number (40509336).

Almost surely, 2135031115 is an apocalyptic number.

135031115 is a deficient number, since it is larger than the sum of its proper divisors (27006229).

135031115 is an equidigital number, since it uses as much as digits as its factorization.

135031115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27006228.

The product of its (nonzero) digits is 225, while the sum is 20.

The square root of 135031115 is about 11620.2889378879. The cubic root of 135031115 is about 513.0321927545.

Adding to 135031115 its reverse (511130531), we get a palindrome (646161646).

The spelling of 135031115 in words is "one hundred thirty-five million, thirty-one thousand, one hundred fifteen".

Divisors: 1 5 27006223 135031115