13503252120043 has 4 divisors (see below), whose sum is σ = 15432288137200. Its totient is φ = 11574216102888.

The previous prime is 13503252120041. The next prime is 13503252120067. The reversal of 13503252120043 is 34002125230531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13503252120043 - 2¹ = 13503252120041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13503252119987 and 13503252120014.

It is not an unprimeable number, because it can be changed into a prime (13503252120041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 964518008568 + ... + 964518008581.

It is an arithmetic number, because the mean of its divisors is an integer number (3858072034300).

Almost surely, 2^{13503252120043} is an apocalyptic number.

13503252120043 is a deficient number, since it is larger than the sum of its proper divisors (1929036017157).

13503252120043 is an equidigital number, since it uses as much as digits as its factorization.

13503252120043 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1929036017156.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 13503252120043 its reverse (34002125230531), we get a palindrome (47505377350574).

The spelling of 13503252120043 in words is "thirteen trillion, five hundred three billion, two hundred fifty-two million, one hundred twenty thousand, forty-three".