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135034113 = 345011371
BaseRepresentation
bin10000000110001…
…11010100000001
3100102002102222110
420003013110001
5234032042423
621222125533
73226525314
oct1003072401
9312072873
10135034113
116a250145
12392808a9
1321c8bc56
1413d1097b
15bcc5193
hex80c7501

135034113 has 4 divisors (see below), whose sum is σ = 180045488. Its totient is φ = 90022740.

The previous prime is 135034099. The next prime is 135034117. The reversal of 135034113 is 311430531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 135034113 - 26 = 135034049 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 135034113.

It is not an unprimeable number, because it can be changed into a prime (135034117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22505683 + ... + 22505688.

It is an arithmetic number, because the mean of its divisors is an integer number (45011372).

Almost surely, 2135034113 is an apocalyptic number.

It is an amenable number.

135034113 is a deficient number, since it is larger than the sum of its proper divisors (45011375).

135034113 is an equidigital number, since it uses as much as digits as its factorization.

135034113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45011374.

The product of its (nonzero) digits is 540, while the sum is 21.

The square root of 135034113 is about 11620.4179356854. The cubic root of 135034113 is about 513.0359895562.

Adding to 135034113 its reverse (311430531), we get a palindrome (446464644).

The spelling of 135034113 in words is "one hundred thirty-five million, thirty-four thousand, one hundred thirteen".

Divisors: 1 3 45011371 135034113