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13503426401 = 13999652199
BaseRepresentation
bin11001001001101110…
…11110111101100001
31021212002002010122202
430210313132331201
5210123334121101
610111533142545
7655425142043
oct144467367541
937762063582
1013503426401
1157aa372133
12274a32aa55
13137278654a
14921573a93
1554074536b
hex324ddef61

13503426401 has 4 divisors (see below), whose sum is σ = 13513080000. Its totient is φ = 13493772804.

The previous prime is 13503426389. The next prime is 13503426457. The reversal of 13503426401 is 10462430531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10462430531 = 71494632933.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13503426401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13503426481) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4824701 + ... + 4827498.

It is an arithmetic number, because the mean of its divisors is an integer number (3378270000).

Almost surely, 213503426401 is an apocalyptic number.

It is an amenable number.

13503426401 is a deficient number, since it is larger than the sum of its proper divisors (9653599).

13503426401 is an equidigital number, since it uses as much as digits as its factorization.

13503426401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9653598.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 13503426401 its reverse (10462430531), we get a palindrome (23965856932).

The spelling of 13503426401 in words is "thirteen billion, five hundred three million, four hundred twenty-six thousand, four hundred one".

Divisors: 1 1399 9652199 13503426401