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135042835 = 527008567
BaseRepresentation
bin10000000110010…
…01011100010011
3100102002212221111
420003021130103
5234032332320
621222234151
73226562614
oct1003113423
9312085844
10135042835
116a256754
1239285957
1321c92c05
1413d13c0b
15bcc7a5a
hex80c9713

135042835 has 4 divisors (see below), whose sum is σ = 162051408. Its totient is φ = 108034264.

The previous prime is 135042829. The next prime is 135042863. The reversal of 135042835 is 538240531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 135042835 - 23 = 135042827 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 135042797 and 135042806.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13504279 + ... + 13504288.

It is an arithmetic number, because the mean of its divisors is an integer number (40512852).

Almost surely, 2135042835 is an apocalyptic number.

135042835 is a deficient number, since it is larger than the sum of its proper divisors (27008573).

135042835 is an equidigital number, since it uses as much as digits as its factorization.

135042835 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27008572.

The product of its (nonzero) digits is 14400, while the sum is 31.

The square root of 135042835 is about 11620.7932173325. The cubic root of 135042835 is about 513.0470351690.

The spelling of 135042835 in words is "one hundred thirty-five million, forty-two thousand, eight hundred thirty-five".

Divisors: 1 5 27008567 135042835