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1350438340531 = 71713278551787
BaseRepresentation
bin10011101001101100011…
…001011100011110110011
311210002201100222122000111
4103221230121130132303
5134111144203344111
62512214404202151
7166365056333020
oct23515431343663
94702640878014
101350438340531
11480799267a45
12199883099357
139a465910b57
144950c1c0547
15251dc003a21
hex13a6c65c7b3

1350438340531 has 16 divisors (see below), whose sum is σ = 1635375522816. Its totient is φ = 1088608150656.

The previous prime is 1350438340519. The next prime is 1350438340549.

1350438340531 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 1350438340531 - 213 = 1350438332339 is a prime.

It is a super-2 number, since 2×13504383405312 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1350438340561) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4117981 + ... + 4433806.

It is an arithmetic number, because the mean of its divisors is an integer number (102210970176).

Almost surely, 21350438340531 is an apocalyptic number.

1350438340531 is a deficient number, since it is larger than the sum of its proper divisors (284937182285).

1350438340531 is a wasteful number, since it uses less digits than its factorization.

1350438340531 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8553138.

The product of its (nonzero) digits is 259200, while the sum is 40.

The spelling of 1350438340531 in words is "one trillion, three hundred fifty billion, four hundred thirty-eight million, three hundred forty thousand, five hundred thirty-one".

Divisors: 1 7 17 119 1327 9289 22559 157913 8551787 59862509 145380379 1017662653 11348221349 79437549443 192919762933 1350438340531