Search a number
-
+
1350442442451 = 3450147480817
BaseRepresentation
bin10011101001101100101…
…001000101111011010011
311210002201122201000210110
4103221230221011323103
5134111201231124301
62512215032132403
7166365136235664
oct23515451057323
94702648630713
101350442442451
114807a0609863
12199884537103
139a466718c1b
144950c96b36b
15251dc5640d6
hex13a6ca45ed3

1350442442451 has 4 divisors (see below), whose sum is σ = 1800589923272. Its totient is φ = 900294961632.

The previous prime is 1350442442449. The next prime is 1350442442497. The reversal of 1350442442451 is 1542442440531.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1350442442451 - 21 = 1350442442449 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1350442442411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 225073740406 + ... + 225073740411.

It is an arithmetic number, because the mean of its divisors is an integer number (450147480818).

Almost surely, 21350442442451 is an apocalyptic number.

1350442442451 is a deficient number, since it is larger than the sum of its proper divisors (450147480821).

1350442442451 is an equidigital number, since it uses as much as digits as its factorization.

1350442442451 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 450147480820.

The product of its (nonzero) digits is 307200, while the sum is 39.

Adding to 1350442442451 its reverse (1542442440531), we get a palindrome (2892884882982).

The spelling of 1350442442451 in words is "one trillion, three hundred fifty billion, four hundred forty-two million, four hundred forty-two thousand, four hundred fifty-one".

Divisors: 1 3 450147480817 1350442442451