Base | Representation |
---|---|
bin | 111110111000111011… |
… | …0100101110010100001 |
3 | 110220121011011020210220 |
4 | 1331301312211302201 |
5 | 4203042323402040 |
6 | 142013142313253 |
7 | 12520524045225 |
oct | 1756166456241 |
9 | 426534136726 |
10 | 135054122145 |
11 | 52304592988 |
12 | 22211428829 |
13 | c974002b57 |
14 | 6772818785 |
15 | 37a690b2d0 |
hex | 1f71da5ca1 |
135054122145 has 16 divisors (see below), whose sum is σ = 216422670912. Its totient is φ = 71916840000.
The previous prime is 135054122141. The next prime is 135054122149. The reversal of 135054122145 is 541221450531.
It is an interprime number because it is at equal distance from previous prime (135054122141) and next prime (135054122149).
It is not a de Polignac number, because 135054122145 - 22 = 135054122141 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (135054122141) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6991606 + ... + 7010895.
It is an arithmetic number, because the mean of its divisors is an integer number (13526416932).
Almost surely, 2135054122145 is an apocalyptic number.
135054122145 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
135054122145 is a deficient number, since it is larger than the sum of its proper divisors (81368548767).
135054122145 is a wasteful number, since it uses less digits than its factorization.
135054122145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14003152.
The product of its (nonzero) digits is 24000, while the sum is 33.
Adding to 135054122145 its reverse (541221450531), we get a palindrome (676275572676).
The spelling of 135054122145 in words is "one hundred thirty-five billion, fifty-four million, one hundred twenty-two thousand, one hundred forty-five".
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