Base | Representation |
---|---|
bin | 10011101001110011001… |
… | …101100001101001101011 |
3 | 11210010000100002111000221 |
4 | 103221303031201221223 |
5 | 134111412440001431 |
6 | 2512234010310511 |
7 | 166400645111503 |
oct | 23516315415153 |
9 | 4703010074027 |
10 | 1350552656491 |
11 | 480847847245 |
12 | 1998b5428437 |
13 | 9a4834c782c |
14 | 4951d45aa03 |
15 | 251e7085111 |
hex | 13a73361a6b |
1350552656491 has 4 divisors (see below), whose sum is σ = 1409272337232. Its totient is φ = 1291832975752.
The previous prime is 1350552656489. The next prime is 1350552656507. The reversal of 1350552656491 is 1946562550531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1350552656491 - 21 = 1350552656489 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1350552656591) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29359840336 + ... + 29359840381.
It is an arithmetic number, because the mean of its divisors is an integer number (352318084308).
Almost surely, 21350552656491 is an apocalyptic number.
1350552656491 is a deficient number, since it is larger than the sum of its proper divisors (58719680741).
1350552656491 is an equidigital number, since it uses as much as digits as its factorization.
1350552656491 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 58719680740.
The product of its (nonzero) digits is 4860000, while the sum is 52.
The spelling of 1350552656491 in words is "one trillion, three hundred fifty billion, five hundred fifty-two million, six hundred fifty-six thousand, four hundred ninety-one".
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