Base | Representation |
---|---|
bin | 11001001001111111… |
… | …10100111011110001 |
3 | 1021212020012020212101 |
4 | 30210333310323301 |
5 | 210124414113203 |
6 | 10112052100401 |
7 | 655452551425 |
oct | 144477647361 |
9 | 37766166771 |
10 | 13505613553 |
11 | 58006263a3 |
12 | 274b004701 |
13 | 1373070c13 |
14 | 921982b85 |
15 | 540a2841d |
hex | 324ff4ef1 |
13505613553 has 4 divisors (see below), whose sum is σ = 13510497280. Its totient is φ = 13500729828.
The previous prime is 13505613551. The next prime is 13505613587. The reversal of 13505613553 is 35531650531.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35531650531 = 13 ⋅2733203887.
It is a cyclic number.
It is not a de Polignac number, because 13505613553 - 21 = 13505613551 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13505613551) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2437713 + ... + 2443246.
It is an arithmetic number, because the mean of its divisors is an integer number (3377624320).
Almost surely, 213505613553 is an apocalyptic number.
It is an amenable number.
13505613553 is a deficient number, since it is larger than the sum of its proper divisors (4883727).
13505613553 is an equidigital number, since it uses as much as digits as its factorization.
13505613553 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4883726.
The product of its (nonzero) digits is 101250, while the sum is 37.
The spelling of 13505613553 in words is "thirteen billion, five hundred five million, six hundred thirteen thousand, five hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •