Search a number
-
+
1350565132233 = 3450188377411
BaseRepresentation
bin10011101001110011111…
…101000111011111001001
311210010001012120022112110
4103221303331013133021
5134111424133212413
62512235133532533
7166401156132102
oct23516375073711
94703035508473
101350565132233
11480853898479
121998b9644149
139a485c75225
1449520d873a9
15251e81eb8c3
hex13a73f477c9

1350565132233 has 4 divisors (see below), whose sum is σ = 1800753509648. Its totient is φ = 900376754820.

The previous prime is 1350565132159. The next prime is 1350565132271. The reversal of 1350565132233 is 3322315650531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a de Polignac number, because none of the positive numbers 2k-1350565132233 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1350565132191 and 1350565132200.

It is not an unprimeable number, because it can be changed into a prime (1350565132283) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 225094188703 + ... + 225094188708.

It is an arithmetic number, because the mean of its divisors is an integer number (450188377412).

Almost surely, 21350565132233 is an apocalyptic number.

It is an amenable number.

1350565132233 is a deficient number, since it is larger than the sum of its proper divisors (450188377415).

1350565132233 is an equidigital number, since it uses as much as digits as its factorization.

1350565132233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 450188377414.

The product of its (nonzero) digits is 243000, while the sum is 39.

The spelling of 1350565132233 in words is "one trillion, three hundred fifty billion, five hundred sixty-five million, one hundred thirty-two thousand, two hundred thirty-three".

Divisors: 1 3 450188377411 1350565132233