1350606416113 has 4 divisors (see below), whose sum is σ = 1351659111408. Its totient is φ = 1349553720820.

The previous prime is 1350606416101. The next prime is 1350606416143. The reversal of 1350606416113 is 3116146060531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1350606416113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1350606416143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 526345723 + ... + 526348288.

It is an arithmetic number, because the mean of its divisors is an integer number (337914777852).

Almost surely, 2^{1350606416113} is an apocalyptic number.

It is an amenable number.

1350606416113 is a deficient number, since it is larger than the sum of its proper divisors (1052695295).

1350606416113 is a wasteful number, since it uses less digits than its factorization.

1350606416113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1052695294.

The product of its (nonzero) digits is 38880, while the sum is 37.

The spelling of 1350606416113 in words is "one trillion, three hundred fifty billion, six hundred six million, four hundred sixteen thousand, one hundred thirteen".