135110035 has 4 divisors (see below), whose sum is σ = 162132048. Its totient is φ = 108088024.

The previous prime is 135110021. The next prime is 135110057. The reversal of 135110035 is 530011531.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 530011531 = 7 ⋅75715933.

It is a cyclic number.

It is not a de Polignac number, because 135110035 - 2¹³ = 135101843 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 135109994 and 135110021.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13510999 + ... + 13511008.

It is an arithmetic number, because the mean of its divisors is an integer number (40533012).

Almost surely, 2^135110035 is an apocalyptic number.

135110035 is a deficient number, since it is larger than the sum of its proper divisors (27022013).

135110035 is an equidigital number, since it uses as much as digits as its factorization.

135110035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27022012.

The product of its (nonzero) digits is 225, while the sum is 19.

The square root of 135110035 is about 11623.6842266125. The cubic root of 135110035 is about 513.1321218591.

Adding to 135110035 its reverse (530011531), we get a palindrome (665121566).

The spelling of 135110035 in words is "one hundred thirty-five million, one hundred ten thousand, thirty-five".