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135112404451 = 1031311770917
BaseRepresentation
bin111110111010101010…
…0111010110111100011
3110220202012211022002211
41331311110322313203
54203202233420301
6142023023422551
712522132326413
oct1756524726743
9426665738084
10135112404451
1152334480282
1222228a54a57
13c9830cb01b
14677a46a643
1537abac0051
hex1f7553ade3

135112404451 has 4 divisors (see below), whose sum is σ = 136424175472. Its totient is φ = 133800633432.

The previous prime is 135112404443. The next prime is 135112404457. The reversal of 135112404451 is 154404211531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 135112404451 - 23 = 135112404443 is a prime.

It is a super-2 number, since 2×1351124044512 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (135112404457) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 655885356 + ... + 655885561.

It is an arithmetic number, because the mean of its divisors is an integer number (34106043868).

Almost surely, 2135112404451 is an apocalyptic number.

135112404451 is a deficient number, since it is larger than the sum of its proper divisors (1311771021).

135112404451 is a wasteful number, since it uses less digits than its factorization.

135112404451 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1311771020.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 135112404451 its reverse (154404211531), we get a palindrome (289516615982).

The spelling of 135112404451 in words is "one hundred thirty-five billion, one hundred twelve million, four hundred four thousand, four hundred fifty-one".

Divisors: 1 103 1311770917 135112404451