13512551546113 has 4 divisors (see below), whose sum is σ = 13512610774960. Its totient is φ = 13512492317268.

The previous prime is 13512551546071. The next prime is 13512551546119. The reversal of 13512551546113 is 31164515521531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13512551546113 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13512551546113.

It is not an unprimeable number, because it can be changed into a prime (13512551546119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29270883 + ... + 29728936.

It is an arithmetic number, because the mean of its divisors is an integer number (3378152693740).

Almost surely, 2^{13512551546113} is an apocalyptic number.

It is an amenable number.

13512551546113 is a deficient number, since it is larger than the sum of its proper divisors (59228847).

13512551546113 is an equidigital number, since it uses as much as digits as its factorization.

13512551546113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 59228846.

The product of its digits is 270000, while the sum is 43.

The spelling of 13512551546113 in words is "thirteen trillion, five hundred twelve billion, five hundred fifty-one million, five hundred forty-six thousand, one hundred thirteen".