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1351304240035 = 5713806490817
BaseRepresentation
bin10011101010100000000…
…000100101101110100011
311210011221201022212211111
4103222200000211232203
5134114432341140120
62512440335324151
7166425402344251
oct23524000455643
94704851285744
101351304240035
114810a3019072
12199a85080657
139a573128019
14495911c15d1
152523d04675a
hex13aa0025ba3

1351304240035 has 8 divisors (see below), whose sum is σ = 1644404033376. Its totient is φ = 1065817428480.

The previous prime is 1351304239979. The next prime is 1351304240047. The reversal of 1351304240035 is 5300424031531.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1351304240035 - 27 = 1351304239907 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1351304239979 and 1351304240006.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1903245054 + ... + 1903245763.

It is an arithmetic number, because the mean of its divisors is an integer number (205550504172).

Almost surely, 21351304240035 is an apocalyptic number.

1351304240035 is a deficient number, since it is larger than the sum of its proper divisors (293099793341).

1351304240035 is an equidigital number, since it uses as much as digits as its factorization.

1351304240035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3806490893.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 1351304240035 its reverse (5300424031531), we get a palindrome (6651728271566).

The spelling of 1351304240035 in words is "one trillion, three hundred fifty-one billion, three hundred four million, two hundred forty thousand, thirty-five".

Divisors: 1 5 71 355 3806490817 19032454085 270260848007 1351304240035