Base | Representation |
---|---|
bin | 11110101110011011110011… |
… | …010101110011000001001011 |
3 | 122201110112012101001010022011 |
4 | 132232123303111303001023 |
5 | 120203002014433103420 |
6 | 1155222535222040351 |
7 | 40314663306656200 |
oct | 3656336325630113 |
9 | 581415171033264 |
10 | 135132343644235 |
11 | 3a06a33a104483 |
12 | 131a56785790b7 |
13 | 5a52c04c375c2 |
14 | 255262439dca7 |
15 | 109518077195a |
hex | 7ae6f357304b |
135132343644235 has 12 divisors (see below), whose sum is σ = 188633720515968. Its totient is φ = 92662178498736.
The previous prime is 135132343644167. The next prime is 135132343644239. The reversal of 135132343644235 is 532446343231531.
It is a de Polignac number, because none of the positive numbers 2k-135132343644235 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (49).
It is not an unprimeable number, because it can be changed into a prime (135132343644239) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 275780292907 + ... + 275780293396.
It is an arithmetic number, because the mean of its divisors is an integer number (15719476709664).
Almost surely, 2135132343644235 is an apocalyptic number.
135132343644235 is a deficient number, since it is larger than the sum of its proper divisors (53501376871733).
135132343644235 is an equidigital number, since it uses as much as digits as its factorization.
135132343644235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 551560586322 (or 551560586315 counting only the distinct ones).
The product of its digits is 9331200, while the sum is 49.
Adding to 135132343644235 its reverse (532446343231531), we get a palindrome (667578686875766).
The spelling of 135132343644235 in words is "one hundred thirty-five trillion, one hundred thirty-two billion, three hundred forty-three million, six hundred forty-four thousand, two hundred thirty-five".
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