13513455554041 has 4 divisors (see below), whose sum is σ = 13514606332672. Its totient is φ = 13512304775412.

The previous prime is 13513455554023. The next prime is 13513455554047. The reversal of 13513455554041 is 14045555431531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13513455554041 - 2¹⁷ = 13513455422969 is a prime.

It is a super-2 number, since 2×13513455554041² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13513455553982 and 13513455554000.

It is not an unprimeable number, because it can be changed into a prime (13513455554047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 575371701 + ... + 575395186.

It is an arithmetic number, because the mean of its divisors is an integer number (3378651583168).

Almost surely, 2^{13513455554041} is an apocalyptic number.

It is an amenable number.

13513455554041 is a deficient number, since it is larger than the sum of its proper divisors (1150778631).

13513455554041 is a wasteful number, since it uses less digits than its factorization.

13513455554041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1150778630.

The product of its (nonzero) digits is 1800000, while the sum is 46.

The spelling of 13513455554041 in words is "thirteen trillion, five hundred thirteen billion, four hundred fifty-five million, five hundred fifty-four thousand, forty-one".