Base | Representation |
---|---|
bin | 1100010010100111110111… |
… | …0001001011100000111001 |
3 | 1202211221012021100221012020 |
4 | 3010221331301023200321 |
5 | 3232403312223014213 |
6 | 44424140434105053 |
7 | 2563234300343256 |
oct | 304517561134071 |
9 | 52757167327166 |
10 | 13514077157433 |
11 | 43403192759a6 |
12 | 162315111b189 |
13 | 7704ab3bb638 |
14 | 34a128a8842d |
15 | 1867eb08e923 |
hex | c4a7dc4b839 |
13514077157433 has 8 divisors (see below), whose sum is σ = 18197173202496. Its totient is φ = 8920182942000.
The previous prime is 13514077157393. The next prime is 13514077157443. The reversal of 13514077157433 is 33475177041531.
13514077157433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13514077157433 - 213 = 13514077149241 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13514077157443) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 22300457053 + ... + 22300457658.
It is an arithmetic number, because the mean of its divisors is an integer number (2274646650312).
Almost surely, 213514077157433 is an apocalyptic number.
It is an amenable number.
13514077157433 is a deficient number, since it is larger than the sum of its proper divisors (4683096045063).
13514077157433 is a wasteful number, since it uses less digits than its factorization.
13514077157433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44600914815.
The product of its (nonzero) digits is 3704400, while the sum is 51.
The spelling of 13514077157433 in words is "thirteen trillion, five hundred fourteen billion, seventy-seven million, one hundred fifty-seven thousand, four hundred thirty-three".
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