Base | Representation |
---|---|
bin | 111110111011100101… |
… | …0111010010001011001 |
3 | 110220211101000201211202 |
4 | 1331313022322101121 |
5 | 4203233143210001 |
6 | 142030050403545 |
7 | 12522656252063 |
oct | 1756712722131 |
9 | 426741021752 |
10 | 135143335001 |
11 | 5234a986914 |
12 | 222372905b5 |
13 | c98963a71c |
14 | 67805dc733 |
15 | 37ae67e96b |
hex | 1f772ba459 |
135143335001 has 4 divisors (see below), whose sum is σ = 135220166400. Its totient is φ = 135066503604.
The previous prime is 135143334959. The next prime is 135143335039. The reversal of 135143335001 is 100533341531.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 100533341531 = 7 ⋅14361905933.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-135143335001 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (135143335081) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38413061 + ... + 38416578.
It is an arithmetic number, because the mean of its divisors is an integer number (33805041600).
Almost surely, 2135143335001 is an apocalyptic number.
It is an amenable number.
135143335001 is a deficient number, since it is larger than the sum of its proper divisors (76831399).
135143335001 is an equidigital number, since it uses as much as digits as its factorization.
135143335001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 76831398.
The product of its (nonzero) digits is 8100, while the sum is 29.
Adding to 135143335001 its reverse (100533341531), we get a palindrome (235676676532).
The spelling of 135143335001 in words is "one hundred thirty-five billion, one hundred forty-three million, three hundred thirty-five thousand, one".
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